Javascript - Loop through sparse array and replace sparse values

Question

I\'m trying to loop through a sparse array and fill in sparse elements with a value.

[\'foo\', \'bar\', , , ,].map(el => el || \'default\') // returns

Answer 1

This should do it:

function Fill(n, _default) {
  return Array.apply(null,n).map(function(val) {
    return val || _default;
  });
}
var newa = Fill(myarray, "default");
console.log(JSON.stringify(newa));

Shown working here: https://jsfiddle.net/6vqsztxg/

Answer 2

Just use a for loop:

for (i = 0; i < arr.length; i++) {
  if (arr[i] === undefined) 
    arr[i] = 'default'
}  

Answer 3

Since .map (and also .forEach) will skip sparse values there's no option except to use a loop, but you should explicitly check for the absence of the missing keys

for (var i = 0, n = a.length; i < n; ++i) {
    if (!(i in a)) {       // explicit check for missing sparse value
        a[i] = "default";
    }
}