Aggregate-function for sum and product in XPath

Question

Similar to this question (http://stackoverflow.com/q/1333558/948404) I want to use XPath to calculate a sum over products in a structure like this:

Answer 1

Use this XPath 2.0 expression:

sum(/items/item/(value * quantity))

Here is an XSLT 2.0 transformation as verification:

<xsl:stylesheet version="2.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="text"/>

    <xsl:template match="/">
        <xsl:sequence select="sum(/items/item/(value * quantity))"/>
    </xsl:template>
</xsl:stylesheet>

When this transformation is applied on the provided XML document:

<items>
    <item>
        <value>1.0</value>
        <quantity>3</quantity>
    </item>
    <item>
        <value>2.5</value>
        <quantity>2</quantity>
    </item>
    <!-- ... -->
</items>

the XPath expression is evaluated and the result of this evaluation is output:

8

Explanation:

In XPath 2.0 it is legal for a location step to be

/(expression),

or even

/someFunction(argumentList)

---

II. XSLT 1.0 solution:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/*">
  <xsl:call-template name="sumProducts">
    <xsl:with-param name="pNodes" select="item"/>
  </xsl:call-template>
 </xsl:template>

 <xsl:template name="sumProducts">
   <xsl:param name="pNodes" select="/.."/>
   <xsl:param name="pAccum" select="0"/>

   <xsl:choose>
    <xsl:when test="not($pNodes)">
     <xsl:value-of select="$pAccum"/>
    </xsl:when>
    <xsl:otherwise>
     <xsl:call-template name="sumProducts">
      <xsl:with-param name="pNodes" select="$pNodes[position() >1]"/>
      <xsl:with-param name="pAccum" select=
      "$pAccum + $pNodes[1]/value * $pNodes[1]/quantity"/>
     </xsl:call-template>
    </xsl:otherwise>
   </xsl:choose>
 </xsl:template>
</xsl:stylesheet>

when this transformation is applied on the provided XML document (above), again the wanted, correct result is produced:

8

Do note: Such kind of problems are easy to solve using the FXSL library. The template to call is transform-and-sum .

Answer 2

Try this:

<xsl:stylesheet version="2.0"xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="text"/>
    <xsl:template match="/">
        <xsl:sequence select="sum(/items/item/(value * quantity))"/>
    </xsl:template>
</xsl:stylesheet>

Answer 3

Based on this suggestion https://stackoverflow.com/a/1334165/948404 I came up with a solution compliant with XSLT 1.0 and XPath 1.0, which are implemented by libxml/libxslt, used by PHPs implementation of XSLTProcessor (thanks to @Dimitre Novatchev for confirmation).

<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="/items">
        <xsl:call-template name="recursivesum">
            <xsl:with-param name="items" select="*" />
        </xsl:call-template>
    </xsl:template>

    <xsl:template name="recursivesum">
        <xsl:param name="items" />
        <xsl:param name="sum" select="0" />
        <xsl:variable name="head" select="$items[1]" />
        <xsl:variable name="tail" select="$items[position()>1]" />
        <xsl:variable name="thissum" select="$head/value * $head/quantity" />
        <xsl:choose>
            <xsl:when test="not($tail)">
                <xsl:value-of select="$sum+$thissum" />
            </xsl:when>
            <xsl:otherwise>
                <xsl:call-template name="recursivesum">
                    <xsl:with-param name="sum" select="$sum+$thissum" />
                    <xsl:with-param name="items" select="$tail" />
                </xsl:call-template>
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>

</xsl:transform>