Django template for loop and display first X matches

Question

Not sure exactly how to phrase my problem but I essentially want to loop through a list and show the first 4 matches only.

{% for reward_type in reward_types %}         


        

Answer 1

Use your view function to prepare your list before passing it to the template.

Django template isn't intended for complex matching like this.

Exactly as discussed ;-)

Answer 2

You may use forloop.counter, The for loop sets a number of variables available within the loop:

forloop.counter The current iteration of the loop (1-indexed)

forloop.counter0 The current iteration of the loop (0-indexed)

forloop.revcounter The number of iterations from the end of the loop (1-indexed)

forloop.revcounter0 The number of iterations from the end of the loop (0-indexed)

forloop.first True if this is the first time through the loop

forloop.last True if this is the last time through the loop

forloop.parentloop For nested loops, this is the loop above the current one

Source

Answer 3

You could have used slice if there isn't {% if category.reward_type == reward_type %}.

i.e. if you have category_matching_rewards which is list having category.reward_type == reward_type then in template it can be done as

{%for category in category_matching_rewards|slice:"4" %}
       Show catgory
       ....
{%endfor%}