Average, max, and min program in C

Question

So I\'m coding in C, and I need to come up with code that will take n numbers from the user, and find their minimum, maximum, average, and sum of squares for for their values. S

Answer 1

int marks , marks_count=0 , max=0 , min=100 , marks_number=1;
float total , avg;

printf("Hit enter to input marks of 10 student.\n\n");
getchar();

do
{
    printf("Input %d Mark : " , marks_number);
    scanf("%d" ,& marks);


    if (marks>max)
    {
        max=marks;
    }

    else if (marks<min)
    {
        min=marks;
    }

    marks_count++;
    marks_number++;

    total=total+marks;
}

while (marks_count<10);
while (marks_number<10);


avg=total/marks_count;

printf("\n\nAverage marks are : %.2f\n" , avg);
printf("Maximum marks are : %d\n" , max);
printf("Minimum marks are : %d\n\n\n" , min);

Answer 2

Add a boolean, moved giving the values min, max 0 are the start of loop

#include<stdio.h>
int main()
{
    float average;
    int i, n, count=0, sum=0, squaresum=0, num, min, max;

    bool first = true;
    printf("Please enter the number of numbers you wish to evaluate\n");
    scanf_s("%d",&n);

    printf("Please enter %d numbers\n",n);
        min=0;
        max=0;

    while(count<n)
    {
            scanf_s("%d",&num);

        if (first) {
           first = false;
           min = max = num;
        }
            if(num>max)
               max=num;
            if(num<min)
               min=num;


        sum = sum+num;
        squaresum = squaresum + (num*num);

        count++;
    }
        average = 1.0*sum/n;

    printf("Your average is %.2f\n",average);
    printf("The sum of your squares is %d\n",squaresum);    



    printf("Your maximum number is %d\n",max);
    printf("Your minimum number is %d\n",min);

return(0);
}

Should also consider to check the return value of scanf