Can you use map to create instances without a wrapper?

Question

In Python, you can give the name of a class as an argument to map in order to create instances of that class:

class Point(object):
    def __init__(         


        

Answer 1

I think your conclusion is correct: init isn't being treated as a conventional func. You might want to report this as a bug; I'm not sure if this is intended behavior or not.

BTW, a more concise way to achieve what you want is:

coords.map{ p => Point(x: p[0], y: p[1]) }

Answer 2

Update for Swift 2:

Filing bugs works!

In Swift 2 this is now possible with coords.map(Point.init):

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Old answer:

• is it because init is not a func?

Yep. In Swift, a function type "consists of a parameter and return type separated by an arrow (->)", and map is defined as func map<U>(transform: (T) -> U) -> [U], i.e. it takes in a function. In the grammar, "function declaration" and "initializer declaration" are treated separately. The latter doesn't have a return type because it's not really a function, just a block of code used to initialize instances. And if you try to pass Point.init, you'll get the error "Initializer cannot be referenced without arguments".

File a bug!

Answer 3

This is now possible in Xcode 7.0 beta 2

from the release notes

Initializers can now be referenced like static methods by referring to .init on a static type reference or type object:

  let x = String.init(5)
  let stringType = String.self
  let y = stringType.init(5)
  let oneTwoThree = [1, 2, 3].map(String.init).reduce(“”, combine: +)