How to print the address of char array

Question

http://ideone.com/4p1gqr

#include     

int main(int argc, char** argv)
{
  float *f = new float[10];

  std::cout << f << std::endl;         


        

Answer 1

You need to cast to void* to invoke correct overload of operator << instead of outputting as C strings

std::cout << static_cast<void*>(c) << std::endl;
std::cout << static_cast<void*>(c+3) << std::endl;