Qualifying a temporary table column name in jOOQ

Question

I am using jOOQ with a temporary table:

Table TMP = DSL.table(\"tmp\");
Field TYPE = DSL.field(\"type\", String.class);
Field

        

Answer 1

There are two ways to interact with tables / columns dynamically (i.e. without using the code generator) in jOOQ:

Using plain SQL (org.jooq.SQL)

That's what you're doing. You can obviously qualify the columns directly in your plain SQL Field references in two ways:

By repeating the "tmp" string in each field:

Table<Record> TMP = DSL.table("tmp");
Field<String> TYPE = DSL.field("tmp.type", String.class);
Field<String> TOKEN = DSL.field("tmp.token", String.class);

By embedding the "tmp" reference in the plain SQL template:

Table<Record> TMP = DSL.table("tmp");
Field<String> TYPE = DSL.field("{0}.type", String.class, TMP);
Field<String> TOKEN = DSL.field("{0}.token", String.class, TMP);

The plain SQL functionality is documented here in the manual

Using qualified references (org.jooq.Name)

That's probably what you want to be doing instead. You'll write:

Table<Record> TMP = DSL.table(DSL.name("tmp"));
Field<String> TYPE = DSL.field(DSL.name("tmp", "type"), String.class);
Field<String> TOKEN = DSL.field(DSL.name("tmp", "token"), String.class);

The naming functionality is described here in the manual.

The advantages of this approach are:

• No SQL injection risk
• Case-sensitivity is taken care of
• Table mapping and other AST transformations will work, too