Is it possible to use OR statement in Doctrine findBy() method?
I want That the output Be like this :
SELECT * FROM `f
I would just use DQL... Add a function like this to your repository:
public function findFriends($userId)
{
return $this->getEntityManager()
->createQuery('SELECT f FROM Friends WHERE userId = :userId OR FriendId = :userId')
->setParameter('userId', $userId)
->getOneOrNullResult();
}
Or use the query builder instead of DQL:
public function findFriends($userId)
{
return $this->getEntityManager()
->createQueryBuilder()
->from('Friends', 'f')
->where('f.userId = :userId')
->orWhere('f.friendId = :userId')
->setParameter('userId', $userId)
->getQuery()
->getOneOrNullResult();
}
And then just use:
$user = $repository->findFriends($this->getRequest()->getSession()->get('id'));
You can use the $or
and $and
keys in the array you pass to findBy
:
$id = $this->getRequest()->getSession()->get('id');
$user = $repo->findBy(
array(
'$or' => array(
array('userId' => $id),
array('FriendId' => $id),
),
);
);
But seeing as this is mongoDB specific, this probably doesn't answer your question. Using the queryBuilder, you could just write this:
$qb = $repository->createQueryBuilder();
$qb->select('f')
->from('friends', 'f')//replace friends with the correct entity name
->where('f.userId = :uid')
->orWhere('f.FriendId = :fid')
->setParameter('uid', $id)
->setParameter('fid', $id);
$users = $qb->getQuery()->getSingleResult();//or more
You could build the or
clause using querybuilder expressions instead, that would look something like this:
$qb->where(
$qb->expr()->orX(
$qb->expr()->eq('f.userId', ':uid'),
$qb->expr()->eq('f.FriendId', ':fid')
)
)
->setParameter('uid', $id)
->setParameter('fid', $id);
Here's some more info
Even though you're using the same value twice, you have to call setParameter
twice. The reason for this can be found here
Lastly, some more docs on the QueryBuilder class