How to print the same char n times in Haskell

Question

I would like to print a char underlining a String n times, with n the length of the String in Haskell.

How should I do this?

My String is: \"Available Chars (x)\

Answer 1

A possibility is to (re)implement replicate, for instance as follows,

replicate' :: Int -> a -> [a]                
replicate' n x = if (n <= 0) then [] else (x : replicate (n-1) x) 

Answer 2

got it!

replicate n 'charHere'

for example, if you want to repeat the char '-' 12 times:

replicate 12 '-'

Answer 3

Use replicate:

underline :: String -> String
underline = flip replicate '-' . length

This will give you a string which is n times the character '-' where n is the length of the input string. It is the same as:

underline = map $ const '-'

You can then use it like this (if for example yourString = "Available Chars (111)"):

> putStrLn yourString >> putStrLn (underline yourString)
Available Chars (111)
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