I want to compare two arrays in PHP

Question

Assume that I have two arrays as follow:

$array1 = array(1, 3, 5);
$array2 = array(\'x\'=> 1, \'y\'=> 2, \'z\'=> 5);

How to check that

Answer 1

array_diff will do the job for you:

<?php
$array1 = array("a" => "green", "red", "blue", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_diff($array1, $array2);
if(empty($result)){
    // arrays contain the same values!
}

?>

Answer 2

Create a class containing an array and make that class implement the Comparable interface, for example http://php.net/manual/language.oop5.interfaces.php#69467

Answer 3

In the simplest case you can just use array_diff. It ignores the keys in your second array, but also the order of the values. It would return an empty set if the arrays are equal:

 if (count(array_diff($array1, $array2)) == 0) {
    // equal

You could also compare the arrays directly, after stripping keys from the second:

 if ($array1 == array_values($array2)) {

That would additionally compare the order of contained values.

Answer 4

Try this

$array1 = array(1, 3, 5);
$array2 = array('x'=> 1, 'y'=> 2, 'z'=> 5);
$array2 = array_values($array2);
echo $array1 == $array2 ? 'true' : 'false';

Answer 5

 array_values($array1) === array_values($array2)

Assuming that arrays have same order.

Answer 6

like this:

<?php    
$array1 = array ("a" => "green", "b" => "brown", "c" => "blue", "red");    
$array2 = array ("a" => "green", "yellow", "red");    
$result = array_diff($array1, $array2);    
if(count($result) == 0)
{
  .......  
}    
?>