Create (L[i], L[i+1]) tuple list from list L [duplicate]

Answer 1

try:

list(zip(l[:-1], l[1:]))

This should do it.

note that

list(zip(l, l[1:]))

works as well, since zip cuts the longest guy, but its less explicit.

Answer 2

A naive approach using list comprehension, this would work as well, though I am not sure if using zip is faster.

L = [1,2,3,4,5]
[(L[i], L[i+1]) for i in range(len(L) - 1)]

Answer 3

You can use the inbuilt zip function: zip(L, L[1:])

In [4]: L = [1,2,3,4,5]

In [5]: zip(L, L[1:])
Out[5]: [(1, 2), (2, 3), (3, 4), (4, 5)]

Answer 4

In [15]: L = [1,2,3,4,5]
In [16]: oL = [(x, y) for x, y in zip(L, L[1:])]
In [17]: oL
Out[17]: [(1, 2), (2, 3), (3, 4), (4, 5)]

Or simply

oL = zip(L, L[1:])