Removing nested bbcode (quotes) in PHP [duplicate]

Answer 1

that the first one is the only one that stays is quite easily found out:

'$found++ ? \'\' : \'$1\''

When starting $found is undefined and evaluates to false so the $1 is returned. Then $found gets incremented to 1 ( undefined + 1 = 1 ) so it is greater that zero and every time it gets called it's further incremented. As everything that is different from zero is evaluated as true after that you always get the '' back.

What you want to do is something like this

$cache = array();

function replace_callback( $matches ) {
    global $cache;
    $hash = sha1sum( $matches[0] );
    $cache[$hash] = $matches[0];
    return "REPLACE:$hash";
}

// replace all quotes with placeholders
$count = 0;
do {
    $input = preg_replace_callback( '~\[quoute.*?\[/quote\]~i', 'replace_callback', $input, -1, $count );
    // replace every occurence
} while ($count > 0);

function undo_replace( $matches ) {
    global $cache;
    return $cache[$matches[1]];
}

// restore the outer most quotes
$input = preg_replace_callback( '~REPLACE:[a-f0-9]{40}~i', 'undo_replace', $input );

// remove the references to the inner quotes
$input = preg_replace( '~REPLACE:[a-f0-9]{40}~i', '', $input );

This code is untested as I don't habe PHP at hand to test it. If there are any errors you cannot fix, please just post them here and I will fix them.

Cheers,
haggi

Answer 2

I've searched for couple of solutions with preg_replace for nested quotes but no one worked. So i tried my littel version according to my requirement.

$position = strrpos($string, '[/quote:');  // this will get the position of last quote
$text = substr(strip_tags($string),$position+17); // this will get the data after the last quote used. 

Hope this will help someone.