Escaping ] and ^ characters in a T-SQL “pattern” expression character class

Question

I\'m trying to emulate Oracle\'s RTRIM(expression, characters) in MsSql Server 2008 R2 with the following query:

REVERSE(
        SUBSTRING(
            


        

Answer 1

I found this document on MS Connect:
http://connect.microsoft.com/SQLServer/feedback/details/259534/patindex-missing-escape-clause

The user asks about ESCAPE clause with PATINDEX, then another user extends the request for CHARINDEX as well.

MS answer: Ticket closed as Won't fix :(

I finished writing my own custom function for LTrim:

CREATE FUNCTION LTrim_Chars (
  @BaseString varchar(2000),
  @TrimChars varchar(100)
)

RETURNS varchar(2000) AS

BEGIN

  DECLARE @TrimCharFound bit

  DECLARE @BaseStringPos int
  DECLARE @TrimCharsPos int

  DECLARE @BaseStringLen int
  DECLARE @TrimCharsLen int

  IF @BaseString IS NULL OR @TrimChars IS NULL
  BEGIN
      RETURN NULL
  END

  SET @BaseStringPos = 1

  SET @BaseStringLen = LEN(@BaseString)
  SET @TrimCharsLen = LEN(@TrimChars)

  WHILE @BaseStringPos <= @BaseStringLen
  BEGIN 

      SET @TrimCharFound = 0
      SET @TrimCharsPos = 1

      WHILE @TrimCharsPos <= @TrimCharsLen
      BEGIN     
          IF SUBSTRING(@BaseString, @BaseStringPos, 1) = SUBSTRING(@TrimChars, @TrimCharsPos, 1)
          BEGIN
              SET @TrimCharFound = 1
              BREAK
          END             
          SET @TrimCharsPos = @TrimCharsPos + 1     
      END

      IF @TrimCharFound = 0
      BEGIN
        RETURN SUBSTRING(@BaseString, @BaseStringPos, @BaseStringLen - @BaseStringPos + 1)
      END       
      SET @BaseStringPos = @BaseStringPos + 1

  END

  RETURN ''

END

And for RTrim:

CREATE FUNCTION RTrim_Chars (
  @BaseString varchar(2000),
  @TrimChars varchar(100)
)

RETURNS varchar(2000) AS

BEGIN

  RETURN REVERSE(LTrim_Chars(REVERSE(@BaseString), @TrimChars))

END

At least, I learnt some MsSql scripting...

---

EDIT:

I added NULL checks for the two arguments, to reflect Oracle and Postgres' behavior.

Unfortunately, Oracle still behaves slightly differently:
in the case you write LTRIM(string, ''), it returns NULL, since a 0-length string is like NULL in Oracle, so it's actually returning the result of LTRIM(string, NULL), which is NULL indeed.

BTW, this is a really strange case.

Answer 2

Not pretty, but...

CREATE FUNCTION dbo.RTRIMCHARS(
    @input AS VARCHAR(MAX), @chars AS VARCHAR(100)
) RETURNS VARCHAR(MAX) 
AS 
BEGIN
    DECLARE @charpos BIGINT
    DECLARE @strpos BIGINT

    SET @strpos = LEN(@input)
    SET @charpos = LEN(@chars)

    IF @strpos IS NULL OR @charpos IS NULL RETURN NULL
    IF @strpos = 0 OR @charpos = 0 RETURN @input

    WHILE @strpos > 0
    BEGIN
        SET @charpos = LEN(@chars)
        WHILE @charpos > 0
        BEGIN
            IF SUBSTRING(@chars, @charpos, 1) = SUBSTRING(@input, @strpos, 1)
            BEGIN
                SET @strpos = @strpos - 1
                BREAK
            END
            ELSE
            BEGIN
                SET @charpos = @charpos - 1
            END
        END
        IF @charpos = 0 BREAK
    END
    RETURN SUBSTRING(@input, 1, @strpos)
END

Usage

SELECT dbo.RTRIMCHARS('bla%123', '123%')   -- 'bla'
SELECT dbo.RTRIMCHARS('bla%123', '123')    -- 'bla%'
SELECT dbo.RTRIMCHARS('bla%123', 'xyz')    -- 'bla%123'
SELECT dbo.RTRIMCHARS('bla%123', ']')      -- 'bla%123'
SELECT dbo.RTRIMCHARS('bla%123', '')       -- 'bla%123'
SELECT dbo.RTRIMCHARS('bla%123', NULL)     -- NULL
SELECT dbo.RTRIMCHARS(NULL, '123')         -- NULL