Im new to PHP MySQL. Im developing a songbook site.
I\'m trying to pull data in a database from the ID in the URL site/publicsong.php?id=12
.
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So I will stick to what you already have with some fixes.
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$servername = "localhost";
$username = "xxxx";
$password = "xxxxxx";
$db_name = "xxxxxxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $db_name);
// Check connection
if ($conn->connect_error){
die("Connection failed: " . $conn->connect_error);
}
$id = $_GET['id'];
$id = mysqli_real_escape_string($conn,$id);
$query = "SELECT * FROM `lyrics_a` WHERE `id`='" . $id . "'";
$result = mysqli_query($conn,$query);
while($row = mysqli_fetch_array($result)) {
echo "<br><br>";
echo $row['id'];
echo $row['eng_title'];
echo $row['eng_lyrics'];
echo $row['alphabet'];
}
?>
No need to use the id as a string,
you can use like : id=" . $id;
Try this:
<?php
$servername = "localhost";
$username = "";
$password = "";
$db_name = "test";
// Create connection
$conn = new mysqli($servername, $username, $password, $db_name);
// Check connection
mysql_select_db($db_name);
$id = $_GET['id'];
$id = mysql_real_escape_string($id);
$query = "SELECT * FROM `lyrics` WHERE `id`='" . $id . "'";
$result = mysql_query($query);
while($row = mysql_fetch_array( $result )) {
echo "<br><br>";
echo $row['title'];
echo $row['content'];
}
?>