I saw array() = range().value
in an example and I\'m trying to understand how it works.
Sub test()
Dim arr() As Variant
arr() = Range(\"E5:E7\
It's basically loading the cell values of E5 - E7 into an array. But it is going to be two dimensional. So you will need Debug.Print arr(i, 1)
Sub test()
Dim arr() As Variant
arr() = Range("E5:E7").Value
For i = 1 To UBound(arr)
Debug.Print arr(i, 1)
Next i
End Sub
This is a good read for you: http://www.cpearson.com/excel/ArraysAndRanges.aspx
The reason you're getting "out of range" is because it returns a 2 dimensional array.
Your line of code For i = 0 To UBound(arr)
should be For i = 1 To UBound(arr,1)
Also, the array starts at 1, so don't use the 0 For i = 1 to UBound(arr, 1)
Your corrected code would be:
Sub Test()
Dim arr() as Variant
arr = Range("E5:E7")
For i = 1 To UBound(arr, 1)
MsgBox (arr(i, 1))
Next i
End Sub
I see two issues with your code. The first is that you start i at 0, but arrays in Excel begin at index 1. Instead of For i = 0
you can use For i = LBound(arr)
like you use UBound(arr)
or just start it at 1.
Second, and more importantly, an array of cells has both columns and rows. When you read a range into a variant array, you get a two-dimensional result (rows and columns) and not a one-dimensional result as you seem to be expecting.
Try this:
Sub test()
Dim arr() As Variant
Dim i As Long, j As Long
arr() = Range("E5:E7").Value
For i = 1 To UBound(arr, 1)
For j = 1 To UBound(arr, 2)
Debug.Print arr(i, j)
Next j
Next i
End Sub
If you want to get just the values of the cells into a one dimensional array, you can do that by using the Transpose
function, like this:
arr() = Application.WorksheetFunction.Transpose(Range("E5:E7").Value)
If you do this, the array is now one-dimensional and you can iterate through it like you were trying to.
arr() = Application.WorksheetFunction.Transpose(Range("E5:E7").Value)
For i = 1 To UBound(arr)
Debug.Print arr(i)
Next i