How to filter array values greater than x

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I\'ve been looking around on the internet and I cant find any posts that cover how to fix this even though I am certain it is a very simple fix.

Basically I have an

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4条回答

南笙

2021-01-20 12:21

I believe you are looking for something like this.

var input = new Array(9,3,4.3,24,54,8,19,23,46,87,3.14);

var newArray = new Array();
input.forEach(function(number){
    if(number > 10)
    {
        newArray.push(number);
    }
});

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刺人心

2021-01-20 12:21

Try using Array.prototype.sort() , Array.prototype.filter()

var input = new Array(9,3,4.3,24,54,8,19,23,46,87,3.14);
var output = new Array();

input = input.sort(function(a, b) {
  return a - b
}).filter(function(val, key) {
  return val < 10 ? val : output.push(val) && null
})

console.log(input, output);

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执笔经年

2021-01-20 12:23

function predicate(x) { return x > 10 }
var output = input.filter(predicate);
input = input.filter(function(x) { return !predicate(x) })

Looks even cleaner with ES6 arrow functions:

var predicate = (x) => x > 10;
var output = input.filter(predicate);
input = input.filter(x => !predicate(x));

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渐次进展

2021-01-20 12:35

    <!DOCTYPE html>
    <html>
    <body>

    <p id="demo"></p>

    <button type="button" onclick="alert(output)">Click Me!</button>
    <script>
    var input = new Array(9,3,4.3,24,54,8,19,23,46,87,3.14);
    var output = new Array();
    for (var i = 0; i < input.length; i ++) {
    if(input[i] > 10)
    {
    output.push(input[i]);
    }
    }


    </script>


    </body>
    </html>

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