'(quote quote) in scheme

Question

I\'m trying to learn scheme by myself. Could anyone tell me why \'(quote quote) will output \'quote, and \'(quote \'quote) will output

Answer 1

This expression:

'(quote quote)

... after expanding '<something> to (quote <something>) is equivalent to (quote (quote quote)), notice that the symbol quote is being quoted two times, and this expression is evaluated and printed as ''quote.

On the other hand, this expression:

'(quote 'quote)

... is equivalent to (quote (quote (quote quote))), notice that the symbol quote is being quoted three times, and this expression is evaluated and printed as '''quote.

Answer 2

Take a look at (free, online) How To Design Programs, intermezzo 2. It explains quote in terms of list and cons. If anything in that explanation doesn't make sense, just back up a bit in the textbook.