Sort documents in collections while fetching

Question

I have a collection called at MongoDB called resource. It has the following documents:

{ \"_id\" : \"Abb.e\", \"_class\" : \"Resource\", \"resourceEmail\" :          


        

Answer 1

Should be something like this:

 MongoOperations mongoOperations = mongoConfiguration.getMongoTemplate();
  List<Resource> resourceList = mongoOperations.findAll(Resource.class).sort({'_id' : 1});
  return resourceList;

You need to append .sort({'_id' : 1}) for ascending order or .sort({'_id' : -1}) for descending order.

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For Java:

.sort( new BasicDBObject( "_id" , 1 ) )

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Solution from echo:

DBCursor dbCursor = mongoOperations.getCollection(RESOURCE_COLLECTION_NAME).find().sort(new BasicDBObject("_id", 1)); 
List<DBObject> dbObjects = dbCursor.toArray(); 
List<Map> items = new ArrayList<Map>(dbCursor.length()); 
for (DBObject dbObject : dbObjects) { 
 Map map = dbObject.toMap(); 
 items.add(dbObject.toMap()); 
}

Answer 2

As you're using Spring Data, you could use a Query object to query all documents in the colletion and sort the results.

MongoOperations mongoOperations = mongoConfiguration.getMongoTemplate();
Query q = new Query().with(new Sort(Sort.Direction.ASC, "_id"));
List<Resource> resourceList = mongoOperations.find(q, Resource.class);
return resourceList;

Of course that you could iterate the list of results and sort it manually, or even use Collection.sort method, but I think if you have an index in the property that you're using to sort, it's faster to mongodb sort the results.