How to Find Next String After the Needle Using Strpos()

Question

I\'m using PHP strpos() to find a needle in a paragraph of text. I\'m struggling with how to find the next word after the needle is found.

For

Answer 1

I did a little testing on my site using the following:

$description = "Hello, this is a test paragraph. The SCREENSHOT mysite.com/screenshot.jpg and the LINK mysite.com/link.html is what I want to return.";

$matches = array();
preg_match('/(?<=SCREENSHOT\s)[^\s]*/', $description, $matches);
var_dump($matches);
echo '<br />';
preg_match('/(?<=LINK\s)[^\s]*/', $description, $matches);
var_dump($matches);

I'm using positive lookbehind to get what you want.

Answer 2

You could do this with a single regular expression:

if (preg_match_all('/(SCREENSHOT|LINK) (\S+?)/', $description, $matches)) {
    $needles = $matches[1]; // The words SCREENSHOT and LINK, if you need them
    $links = $matches[2]; // Contains the screenshot and/or link URLs
}

Answer 3

Or the "old" way... :-)

$word = "SCREENSHOT ";
$pos = strpos($description, $word);
if($pos!==false){
    $link = substr($description, $pos+strlen($word));
    $link = substr($link, strpos($link, " "));
}