Batch file - Discovered program path (variable) - Run program from discovered reg value (path)

Question

I\'m trying to create a batch file that will discovered the location of a EXE in this case Steam, and runs that EXE with the discovered path from the registry. The reason I

Answer 1

@echo off

for /f "tokens=1,3" %%E in ('reg query "HKEY_CURRENT_USER\Software\Valve\Steam"') do (
    if %%E==SteamExe echo "%%F"
)

pause

reg query Get all keys and values for the registry path.

for /f Visit each line of the queried registry data and split the data so "Name" is stored in 'E' and "Data" is stored in 'F'. If 'E' equals "SteamExe" then echo 'F', which will display the steam executable path.

Command-line version:

@for /f "tokens=1,3" %E in ('reg query "HKEY_CURRENT_USER\Software\Valve\Steam"') do @if %E==SteamExe @echo "%F"

Answer 2

I approached another way, this will work.

setlocal

regedit /e reg_exported.tmp "HKEY_CURRENT_USER\Software\Valve\Steam"
find "SteamExe" reg_exported.tmp | findstr "SteamExe" >> line_exported.tmp
set /p SteamPath= < line_exported.tmp
set SteamPath=%SteamPath:~11%

del reg_exported.tmp
del line_exported.tmp

start "Steam" %SteamPath%

endlocal