C++ Macro to conditionally compile code?

Question

I want to compile code conditionally based on a macro. Basically I have a macro that looks like (Simplified from the real version):

#if DEBUG
    #define STA         


        

Answer 1

Would:

#if DEBUG
    #define START_BLOCK( x ) if(DebugVar(#x) \
        { char debugBuf[8192];
    #define END_BLOCK( ) printf("%s\n", debugBuf); }
#else
    #define START_BLOCK( x ) {
    #define END_BLOCK( ) }
#endif

do?

Answer 2

So you want conditional blocks with their own scope?

Here's a quite readable solution that relies on the compiler to optimize it away:

#define DEBUG 1

if (DEBUG) {
    // ...
}

And here is one that is preprocessor-only:

#define DEBUG 1

#ifdef DEBUG
    #define IFDEBUG(x) {x}
#else
    #define IFDEBUG(x)
#endif

IFDEBUG(
    // ...
)

Or manually:

#define DEBUG 1

#ifdef DEBUG
{
    // ...
}
#endif