System.out.print of string without 'ln'

Question

I have a byte array which looks like this:

[0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116,          


        

Answer 1

You can use a String(byte[],Charset) constructor and specify a Charset to be used to decode this array of bytes:

System.out.println(new String(byteArray, StandardCharsets.UTF_8));

In most cases, StandardCharsets.UTF_8 is a default charset.

Answer 2

Try this.

byte[] bytes = new byte[]{0, 0, 0, 0, 0, 0, 0, 0, 122, 98, 117, 54, 46, 0, 0, 115, 122, 42, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 116, 121, 116, 117, 108, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 32, 107, 111, 98, 105, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 122, 42, 109, 111, 119, 40, 0, 0, 0, 0, 0, 0, 107, 111, 98, 0, 0, 0, 0, 0, 98, 111, 40};
System.out.println(new String(bytes));

Answer 3

Your byte array is mostly non printable characters, with a few random letters mixed in. But all you need is:

String myString = new String(byteArray);

which will give you a valid string.

Try out the following code, as maybe it will better illustrate the issue your having:

for (char c : new String(byteArray).toCharArray()) {
    System.out.printf("Character: %s Hex: %02x \n", c, (int) c);
}

Answer 4

try this

System.out.println(Arrays.toString(byteArray));