Passing a 2d dynamic array to a function in C++

Question

I have this 2d dynamic array and I want to pass it to a function, How would I go about doing that

int ** board;
        board = new int*[boardsize];

                


        

Answer 1

  void function(int *board[boardSize]){}


  function(board);

Answer 2

You should define a function to take this kind of argument

void func(int **board) {
    for (int i=0; i<boardsize; ++i) {
        board[i] = new int [size]; 
    }
}

func(board);

If boardsize or size are not globlal, you can pass it through parameters.

void func(int **board, int boardsize, int size) {
    for (int i=0; i<boardsize; ++i) {
        board[i] = new int [size];
    }
}

func(board, boardsize, size);

Answer 3

Small code for creation and passing a dynamic double dimensional array to any function. `

 void DDArray(int **a,int x,int y)
 {
   int i,j;
    for(i=0;i<3;i++)
     {
      for(j=0;j<5;j++)
       {
         cout<<a[i][j]<<"  ";
       }

       cout<<"\n";
     }
  }

int main()
{
  int r=3,c=5,i,j;
  int** arr=new int*[r];
  for( i=0;i<r;i++)
   {
    arr[i]=new int[c];
   }

  for(i=0;i<r;i++)
   {
     for(j=0;j<c;j++)
      {
        cout<<"Enter element at position"<<i+1<<j+1;
        cin>>arr[i][j];
      }
   }
   DDArray(arr,r,c);

}

`

Answer 4

You can pass a pointer to an pointer:

void someFunction(int** board)
{


}

Answer 5

int **board; 
board = new int*[boardsize]; 

for (int i = 0; i < boardsize; i++)
    board[i] = new int[size];

You need to allocate the second depth of array.

To pass this 2D array to a function implement it like:

fun1(int **);

Check the 2D array implementation on below link:

http://www.codeproject.com/Articles/21909/Introduction-to-dynamic-two-dimensional-arrays-in