I have the following app that shows that the key part of a Dictionary is not sent to JsonConverter
, but it is called ToString()
on. This is an issu
Based on the information you have provided, I would suggest that instead of using a Tuple as your key, use a custom struct or object and override the ToString method. Then you can serialize/deserialize as you wish.
I also had the same problem with Deserializing a Dictionary with Tuple as key. JSON converts the tuple into a mere string. But in my case, i cannot avoid using Tuple as key in the dictionary. So i made a custom JSON convertor to Deserialize the Dictionary with Tuple as key and it worked well.
I have modified the same as per your code. Hope it will work fine and can give you an idea about JSON CustomConverter. Also explained better with comments.
public class TupleKeyConverter : JsonConverter
{
/// <summary>
/// Override ReadJson to read the dictionary key and value
/// </summary>
/// <param name="reader"></param>
/// <param name="objectType"></param>
/// <param name="existingValue"></param>
/// <param name="serializer"></param>
/// <returns></returns>
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
Tuple<string, string> _tuple = null;
string _value = null;
var _dict = new Dictionary<Tuple<string, string>, string>();
//loop through the JSON string reader
while (reader.Read())
{
// check whether it is a property
if (reader.TokenType == JsonToken.PropertyName)
{
string readerValue = reader.Value.ToString();
if (reader.Read())
{
// check if the property is tuple (Dictionary key)
if (readerValue.Contains('(') && readerValue.Contains(')'))
{
string[] result = ConvertTuple(readerValue);
if (result == null)
continue;
// Custom Deserialize the Dictionary key (Tuple)
_tuple = Tuple.Create<string, string>(result[0].Trim(), result[1].Trim());
// Custom Deserialize the Dictionary value
_value = (string)serializer.Deserialize(reader, _value.GetType());
_dict.Add(_tuple, _value);
}
else
{
// Deserialize the remaining data from the reader
serializer.Deserialize(reader);
break;
}
}
}
}
return _dict;
}
/// <summary>
/// To convert Tuple
/// </summary>
/// <param name="_string"></param>
/// <returns></returns>
public string[] ConvertTuple(string _string)
{
string tempStr = null;
// remove the first character which is a brace '('
if (_string.Contains('('))
tempStr = _string.Remove(0, 1);
// remove the last character which is a brace ')'
if (_string.Contains(')'))
tempStr = tempStr.Remove(tempStr.Length - 1, 1);
// seperate the Item1 and Item2
if (_string.Contains(','))
return tempStr.Split(',');
return null;
}
/// <summary>
/// WriteJson needs to be implemented since it is an abstract function.
/// </summary>
/// <param name="writer"></param>
/// <param name="value"></param>
/// <param name="serializer"></param>
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
serializer.Serialize(writer, value);
}
/// <summary>
/// Check whether to convert or not
/// </summary>
/// <param name="objectType"></param>
/// <returns></returns>
public override bool CanConvert(Type objectType)
{
return true;
}
}
Now declare a property as follows. JsonConvertor Property is important.
[JsonConverter(typeof(TupleKeyConverter))]
public Dictionary<Tuple<int,string>,string> MyDict {get; set;}
Or you could try this to replace this in your code. though i never tested.
coll2 = JsonConvert.DeserializeObject<Dictionary<Tuple<string, string>, string>>("", new TupleKeyConverter());