i have a ajax code that works properly and gives the desired result. I want to modify this code and want that when a reply is received from ajax a popup/modal box should get
Try put this inside success callback :
success: function (returndata) {
if (returndata[4] === 1) {
$('#bsModal3').modal(); // this
} else {
// other code
}
},
You can use $("#bsModal3").modal('show');
inside your result.
See more about modal methods
$.ajax({
type: 'post',
url: 'test2.php',
dataType: 'json',
data: {
txt: txtbox,
hidden: hiddenTxt
},
cache: false,
success: function(returndata) {
if (returndata[4] === 1) {
$("#bsModal3").modal('show');
} else {
// other code
}
},
error: function() {
console.error('Failed to process ajax !');
}
});
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<!-- Modal -->
<div class="modal fade" id="bsModal3" tabindex="-1" role="dialog" aria-labelledby="mySmallModalLabel" aria-hidden="true">
<div class="modal-dialog modal-sm">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h4 class="modal-title" id="mySmallModalLabel">Modal title</h4>
</div>
<div class="modal-body">
Your content goes here...
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary">Save changes</button>
</div>
</div>
</div>
</div>
Please do with the Ajax Call,modal is call in ajax response
$.ajax({
type: 'post',
url: 'test2.php',
dataType: 'json',
data: {
txt: txtbox,
hidden: hiddenTxt
},
cache: false,
success: function (returndata) {
if (returndata[4] === 1) {
$('#bsModal3').modal(); // Please right this in your Code
} else {
// other code
}
},
error: function () {
console.error('Failed to process ajax !');
}
});