Filter out an array from another array [duplicate]

Answer 1

Use _.differenceBy() to find items in the 1st array (allCodes) that are not found in the 2nd array (balanceCodes):

var balanceCodes = [
    { ID: 1, StringValue: "dummy" },
    { ID: 2, StringValue: "data" }
];
var allCodes = [
    { ID: 1, StringValue: "dummy", Color: "red", Order: "low" },
    { ID: 2, StringValue: "data", Color: "green", Order: "medium" },
    { ID: 3, StringValue: "extra", Color: "black", Order: "low" },
    { ID: 4, StringValue: "options", Color: "grey", Order: "high" }
];

var result = _.differenceBy(allCodes, balanceCodes, 'ID');

console.log(result);

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Answer 2

You can achieve this by using filter and every, without having to use lodash:

var balanceCodes = [
    { ID: 1, StringValue: "dummy" },
    { ID: 2, StringValue: "data" }
];

var allCodes = [
    { ID: 1, StringValue: "dummy", Color: "red", Order: "low" },
    { ID: 2, StringValue: "data", Color: "green", Order: "medium" },
    { ID: 3, StringValue: "extra", Color: "black", Order: "low" },
    { ID: 4, StringValue: "options", Color: "grey", Order: "high" }
];

var result = allCodes.filter((code) => 
  balanceCodes.every((balanceCode) => balanceCode.ID !== code.ID));

console.log(result);

Answer 3

_.remove would be your best bet. If the IDs are unique - something like this should suffice (using lodash):

for( let balanceCode of balanceCodes){
    _.remove( allCodes, (code) => { code.ID === balanceCode.ID })
}