Insert into 2 tables from 1 form. Mysql Transaction?

Question

The user will create an article and submit an image with it.

+The article will go to the articles table.

+The image will go to images table (so that it can

Answer 1

$sql ='START TRANSACTION;
       INSERT INTO articles (article_id,article_title, article_text, article_date) VALUES (NULL,?, ?, NOW());
       INSERT INTO images (article_id, image_caption) VALUES(LAST_INSERT_ID(),?);
       COMMIT;';

Answer 2

$mysqli->query("START TRANSACTION");
$stmt = $mysqli->prepare('INSERT INTO articles(article_title, article_text, article_date) VALUES (?, ?, NOW())');
$stmt->bind_param('ss', $_POST['article_name'], $_POST['description']);
$stmt->execute();
$stmt = $mysqli->prepare('INSERT INTO images (article_id, image_caption) VALUES(LAST_INSERT_ID(),?)');
$stmt->bind_param('s', $_POST['image_caption']);
$stmt->execute();
$stmt->close();
$mysqli->query("COMMIT");

Answer 3

It looks like you are using PDO (nice!). With PDO, you can get your transactions in an easy way with beginTransaction() and commit()

Your code would look like:

$pdo->beginTransaction();
// .. fire your 'normal' queries.
// .. and yet some more queries
$pdo->commit();

Then, I'd personally write separate INSERT queries in just two separate statements. More readable in my opinion.

Example:

$pdo->beginTransaction();

$first = $pdo->prepare('INSERT INTO table (field, otherField) VALUES(?,?)');
$second = $pdo->prepare('INSERT INTO table (field, otherField) VALUES(?,?)');

$first->execute(array( .. your data (values) .. ));
$second->execute(array( .. your data (values) .. ));

$pdo->commit();