C# declaring a 2D array

Question

I am trying to setup a 2d array in C# to act as a maze to move a character around, I am having a few issues initialising the array, I am trying to do the below

but t

Answer 1

Two-Dimensional Arrays

The simplest form of the multidimensional array is the 2-dimensional array. A 2-dimensional array is a list of one-dimensional arrays.

A 2-dimensional array can be thought of as a table, which has x number of rows and y number of columns. Following is a 2-dimensional array, which contains 3 rows and 4 columns −

Two Dimensional Arrays in C#

Thus, every element in the array a is identified by an element name of the form a[ i , j ], where a is the name of the array, and i and j are the subscripts that uniquely identify each element in array a.

Initializing Two-Dimensional Arrays

int [,] a = new int [3,4] {

   {0, 1, 2, 3} ,   /*  initializers for row indexed by 0 */

   {4, 5, 6, 7} ,   /*  initializers for row indexed by 1 */

   {8, 9, 10, 11}   /*  initializers for row indexed by 2 */

};

Explain above code:

new int [**3**,4] **3** denoting to rows like how may object in array 

eg:

{0, 1, 2, 3} ,  
{4, 5, 6, 7} ,  
{8, 9, 10, 11}


new int [3,**4**] **4** denoting to columns like total value in object (4 columns)

eg:   


   {0, 1, 2, 3}

Let us check the program to handle a two dimensional array

 using System;
    namespace ArrayApplication {
       class MyArray {
          static void Main(string[] args) {
             /* an array with 5 rows and 2 columns*/
             int[,] a = new int[5, 2] {{0,0}, {1,2}, {2,4}, {3,6}, {4,8} };
             int i, j;

             /* output each array element's value */
             for (i = 0; i < 5; i++) {

                for (j = 0; j < 2; j++) {
                   Console.WriteLine("a[{0},{1}] = {2}", i, j, a[i,j]);
                }
             }
             Console.ReadKey();
          }
       }
    }

Output:  

a[0,0]: 0
a[0,1]: 0
a[1,0]: 1
a[1,1]: 2
a[2,0]: 2
a[2,1]: 4
a[3,0]: 3
a[3,1]: 6
a[4,0]: 4
a[4,1]: 8

Answer 2

You can't initialize an array like that other than in a variable declaration. However, the change is simple:

maze = new int[,] { 
   // As before
};

As asides:

• It looks like maze should be an instance variable rather than a static variable. After all, you're initializing it each time you create an instance of Maze
• You have a finalizer for no reason. Finalizers are very rarely required (or indeed advisable) in C#

Answer 3

Ok, well here is some extract from the msdn :

 int[,] myArray = {{1,2}, {3,4}, {5,6}, {7,8}};

extracted from MSDN multidimensional arrays

you should also read up concerning Destructors, finalizers etc ... , I bet your coming from C++ ? Differences between the 2 languages arent always obvious :).

Answer 4

Just to make Jon's post a bit clearer:

maze = new int[,]{
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0},    
{0, 0, 2, 2, 2, 2, 2, 2, 2, 2, 0, 2, 2, 2, 2, 2, 2, 2, 2, 0, 0},     
{0, 0, 3, 0, 0, 2, 0, 0, 0, 2, 0, 2, 0, 0, 0, 2, 0, 0, 3, 0, 0},     
{0, 0, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 0, 0},    
{0, 0, 2, 0, 0, 2, 0, 2, 0, 0, 0, 0, 0, 2, 0, 2, 0, 0, 2, 0, 0},    
{0, 0, 2, 2, 2, 2, 0, 2, 2, 2, 0, 2, 2, 2, 0, 2, 2, 2, 2, 0, 0},     
{0, 0, 0, 0, 0, 2, 0, 0, 0, 1, 0, 1, 0, 0, 0, 2, 0, 0, 0, 0, 0},    
{0, 0, 0, 0, 0, 2, 0, 1, 1, 1, 4, 1, 1, 1, 0, 2, 0, 0, 0, 0, 0},     
{0, 0, 0, 0, 0, 2, 0, 1, 0, 0, 0, 0, 0, 1, 0, 2, 0, 0, 0, 0, 0},     
{1, 1, 1, 1, 1, 2, 1, 1, 0, 0, 0, 0, 0, 1, 1, 2, 1, 1, 1, 1, 1},
{0, 0, 0, 0, 0, 2, 0, 1, 0, 0, 0, 0, 0, 1, 1, 2, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 2, 0, 1, 1, 1, 1, 1, 1, 1, 0, 2, 0, 0, 0, 0, 0},
{0, 0, 0, 0, 0, 2, 0, 1, 0, 0, 0, 0, 0, 1, 0, 2, 0, 0, 0, 0, 0},
{0, 0, 2, 2, 2, 2, 2, 2, 2, 2, 0, 2, 2, 2, 2, 2, 2, 2, 2, 0, 0},
{0, 0, 2, 0, 0, 2, 0, 0, 0, 2, 0, 2, 0, 0, 0, 2, 0 ,0, 2, 0, 0},
{0, 0, 3, 2, 0, 2, 2, 2, 2, 2, 5, 2, 2, 2, 2, 2, 0, 2, 3, 0, 0},
{0, 0, 0, 2, 0, 2, 0, 2, 0, 0, 0, 0, 0, 2, 0, 2, 0, 2, 0, 0, 0},
{0, 0, 2, 2, 2, 2, 0, 2, 2, 2, 0, 2, 2, 2, 0, 2, 2, 2, 2, 0, 0},
{0, 0, 2, 0, 0, 0, 0, 0, 0, 2, 0, 2, 0, 0, 0, 0, 0, 0, 2, 0, 0},
{0, 0, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 0, 0},
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0}
};

Boy, that was a big maze array...

Answer 5

You need to declare maze

 numbers = new int[X,Y]; where X and Y are how big it is