mongodb subelement querying

Question

here is the example

> db.test.insert({ name: \'test\', values: [ { check: true }, { check: false } ] })
> db.find({ values.check: true })[0]


        

Answer 1

> db.test.aggregate(
{ $unwind: "$values" },
{ $match: { "values.check": true } }
).result

[
        {
                "_id" : ObjectId("50e22046dc278908f3a38a8e"),
                "name" : "test",
                "values" : {
                        "check" : true
                }
        }
]

Answer 2

You can use the $ projection operator to include just the first values array element that matched the query:

 db.test.find({ 'values.check': true }, {name: 1, 'values.$': 1})

returns:

{
    "_id": ObjectId("50e22046dc278908f3a38a8e"), 
    "name": "test", 
    "values": [ { "check": true } ] }

Answer 3

$fetchcode = "Fetch an array from the mongo db"
   foreach ($fetchcode as $mainkey => $mainVariable) {
        foreach($mainVariable as $key2 => $doc2)
        {
            if($key2 == "check"){
                if($doc2 == "true")
                {
                   //Your Function Here
                }
            }
        }
    }

You can try this