I have a column Month in my table. The month name and date are stored in this month column like
Month
01-JAN-12
02-FEB-12
Use TO_CHAR
function as in TO_CHAR(my_column, 'MM')
.
For your specific format you would need the format converter TO_CHAR(month, 'FmMM')
(thanks to Nicholas Krasnov for this trick).
If your month
column is not already of a date type you will first need to convert it to a date: TO_CHAR(TO_DATE(month, 'DD-Mon-IY'), 'FmMM')
.
select
to_char(to_date('01-JAN-12','dd-mon-yy'),'mm') from dual;
You can use the "DatePart" function too :
http://docs.oracle.com/cd/E10530_01/doc/epm.931/html_esb_techref/maxl/dml/funcs/datepart.htm
Totally agree regarding writing a case when Oracle offers built-in functionality:
SELECT EXTRACT(MONTH FROM DATE '2012-03-15') FROM DUAL;
SELECT EXTRACT(MONTH FROM TO_DATE('01-JAN-12', 'DD-MON-RR')) month_to_number FROM DUAL;
select to_number(to_char(to_date('01-JAN-12','dd-mon-yy'),'mm')) month_to_number from dual;
select to_number(to_char(trunc(sysdate), 'mm')) month_to_number from dual;
SELECT ( CASE yourDate
WHEN 'Jan' THEN 1
WHEN 'Feb' THEN 2
WHEN 'Mar' THEN 3
WHEN 'Apr' THEN 4
WHEN 'May' THEN 5
WHEN 'Jun' THEN 6
WHEN 'Jul' THEN 7
WHEN 'Aug' THEN 8
WHEN 'Sep' THEN 9
WHEN 'Oct' THEN 10
WHEN 'Nov' THEN 11
WHEN 'Dec' THEN 12
END )
Extract works perfectly for this
EXTRACT extracts and returns the value of a specified datetime field
with fullYear as(
select (to_date('01-jan-12') + 29*level) dte
from dual
connect by level <= 12
)
select extract(month from dte) month, dte from fullYear ;
gives you
MONTH DTE
1 January, 30 2012 00:00:00+0000
2 February, 28 2012 00:00:00+0000
3 March, 28 2012 00:00:00+0000
4 April, 26 2012 00:00:00+0000
5 May, 25 2012 00:00:00+0000
6 June, 23 2012 00:00:00+0000
7 July, 22 2012 00:00:00+0000
8 August, 20 2012 00:00:00+0000
9 September, 18 2012 00:00:00+0000
10 October, 17 2012 00:00:00+0000
11 November, 15 2012 00:00:00+0000
12 December, 14 2012 00:00:00+0000