How to compare two arrays of integers order-insensitively

Question

I want Java code that can compare in this way (for example):

<1 2 3 4>  = <3 1 2 4>
<1 2 3 4> != <3 4 1 1>

I can\'t

Answer 1

I think it would be sensible to check that the lengths of both arrays are equal before doing any iterating. It's a cheap way to opt out of hard work early, and it fixes the following type of failure for the second approach you mention:

{1, 2, 3} seen as equal to {4, 3, 2, 1}

Answer 2

if you take one array as 1,2,3,4,3,1,2,4 then the solution is in this way.

2n = total number of integers : 8

//program
int i, j, n = 4;
for(i = 0; i < n; i++)
  for(j = n; j < 2n; j++)
   {
     if( a[i] != a[j])
      { 
        j++;
      }
     else
     {
       i++; exit();
     }
  }  

if (i == n) 
{ //They both are equal;
}
else if(i != n)
{
//They both are not equal;
}

If it is not working please comment on it. Thank You.