I want to replace all occurrences of a number with a random number in each line of a file using \"sed\". For example, if my file has the number 892 in each line, I would lik
With GNU sed, you could do something like
sed '/;892$/ { h; s/.*/echo $((RANDOM % 100 + 800))/e; x; G; s/892\n// }' filename
...but it would be much saner to do it with awk:
awk -F \; 'BEGIN { OFS = FS } $NF == 892 { $NF = int(rand() * 100 + 800) } 1' filename
To make sure that the random numbers are unique, amend the awk code as follows:
awk -F \; 'BEGIN { OFS = FS } $NF == 892 { do { $NF = int(rand() * 100 + 800) } while(!seen[$NF]++) } 1'
Doing that with sed would be too crazy for me. Be aware that this will only work only if there are less than 100 lines with a last field of 892 in the file.
The sed code reads
/;892$/ { # if a line ends with ;892
h # copy it to the hold buffer
s/.*/echo $((RANDOM % 100 + 800))/e # replace the pattern space with the
# output of echo $((...))
# Note: this is a GNU extension
x # swap pattern space and hold buffer
G # append the hold buffer to the PS
# the PS now contains line\nrandom number
s/892\n// # remove the old field and the newline
}
The awk code is much more straightforward. With -F \;
, we tell awk to split the lines at semicolons, then
BEGIN { OFS = FS } # output field separator is input FS, so the output
# is also semicolon-separated
$NF == 892 { # if the last field is 892
# replace it with a random number
$NF = int(rand() * 100 + 800)
}
1 # print.
The amended awk code replaces
$NF = int(rand() * 100 + 800)
with
do {
$NF = int(rand() * 100 + 800)
} while(!seen[$NF]++)
...in other words, it keeps a table of random numbers it has already used and keeps drawing numbers until it gets one it hasn't seen before.