Allocate a string array from inside a function in C

Question

I have a function that scans a file and returns the number of the lines along with the lines in a string array, my function looks like this :

int load_lines(         


        

Answer 1

When you pass an argument into a function, the function always works on a copy of that argument.

So in your case, load_lines is working on a copy of _array. The original _array is not modified:

char** _array = NULL;
printf("%p\n", _array); // Prints "0x0000"
line_number = load_lines(inname, _array);
printf("%p\n", _array); // Prints "0x0000"

To modify _array, you need to pass a pointer to it:

int load_lines(char* _file, char*** _array){
    ...
    (*array) = malloc (line_number * sizeof(char*));
    ...
    (*array)[line_number] = malloc(strlen(line_buffer) + 1);
}

char** _array = NULL;
line_number = load_lines(inname, &_array);

[However, any time you find yourself needing a triple pointer (i.e. ***), it's time to reconsider your architecture.]

Answer 2

If you want to return a newly allocated array of strings from the function, then the second argument of the function must have a type of char***, eg. a pointer to an array of strings:

int load_lines(char* _file, char*** _array) {
    ...
    char** tmparray = malloc(line_number * sizeof(char*));
    ...
        tmparray[line_number] = malloc(strlen(line_buffer) + 1);
        strcpy(tmparray[line_number], line_buffer);
    ...
    (*_array) = tmparray;
}

And when you call the function:

char** _array;
line_number = load_hosts(inname, &_array);