I realize this is a contrived example, but I want a compile check to prevent this...
class A {};
class B : public A {};
class C : public A {};
class D : pub
If you really want to, you an test both your base classes:
class A {};
class B : public A {};
class C : public A {};
class D : public B, public C
{
static_assert(!(is_base_of<A,B>::value && is_base_of<A,C>::value),
"Invalid inheritance!");
};
Otherwise you can make the classes inherit virtually from A, so that there will still only be one instance of it in the derived class:
class A {};
class B : public virtual A {};
class C : public virtual A {};
class D : public B, public C
{
// only one A here
};
When I try to derive a class twice as you have here it does not even compile. (duplicate base type)
The following should work:
BOOST_STATIC_ASSERT(((A*)(D*)0 == 0))
If A exists twice, this should rise an ambiguity error, while otherwise the test will always succeed (because it compares two null pointers).