How to match nested function invocations (bracket pairs) using a regular [removed]recursive?)

Question

I\'m looking for a regular expression (**) that will match an unknown number of nested functions. So

expression
function(expression)
function(function(expres         


        

Answer 1

Worth noting as per Bart Kiers's answer that some regex engines (excluding Javascript) have extended features to provide recursive matching - but such a feature shouldn't be considered to be a regular expression as per the formal definition.

Answer 2

I'm looking for a regular expression (**) that will match an unknown number of nested functions.

Some regex implementations support recursive matching (Perl, PHP, .NET), but JavaScript does not. So, the answer to your question is: no, that is not possible.

Answer 3

This isn't recursive, but it does the trick.

PRECONDITIONS:

• Function names are alpha-numeric/underscore with possible leading white space.
• Function names do not start with a number.
• Expressions have no parentheses in them.
• There is only one expression nested within the functions.

CODE:

var target = "function(function(function(expression)))";
var pattern = /\s*([a-zA-Z_]\w*[(](\s*[a-zA-Z_]\w*[(]|[^()]+[)]|[)])+[)])/;
var matches = target.match(pattern);
var target= matches[1];

REGULAR EXPRESSION DISSECTION:

\s*             // 0+ white space characters
(               // Capture group for what you want
  [a-zA-Z_]     //   1 letter/underscore
  \w*           //   0+ word characters (alpha-numeric/underscore)
  [(]           //   left parenthesis
  (             //   PIECES:
    \s*         //     0+ white space characters
    [a-zA-Z_]   //     1 letter/underscore
    \w*         //     0+ word characters (alpha-numeric/underscore)
    [(]         //     left parenthesis
   |            //   OR
    [^()]+      //     1+ non-parenthesis characters
    [)]         //     right parenthesis
   |            //   OR
    [)]         //     right parenthesis
  )+            //   1+ of these PIECES
  [)]           //   right parenthesis
)