I\'m fairly new to programming in general and MATLAB and I\'m having some problems with removing values from matrix.
I have matrix tmp2 with values:
use unique
without 'rows'
option
[C ia ib] = unique( tmp2(:,1) );
C = tmp2( ia, : );
You can do this using unique
:
>> [~,b] = unique(tmp2(:,1)); % indices to unique values in first column of tmp2
>> tmp2(b,:) % values at these rows
ans =
0.6000 20.4000
0.7000 20.4000
0.8000 20.4000
0.9000 20.4000
1.0000 19.1000
...
By default, unique
saves the last unique value it finds, and the output will be sorted. This happens to be what you want/have, so you're in luck :)
If this is not what you want/have, you'll have to tinker a bit more. Removing duplicates preserving the order goes like this:
% mess up the order
A = randperm(size(tmp2,1));
tmp2 = tmp2(A,:)
% use third output of unique
[a,b,c] = unique(tmp2(:,1));
% unique values, order preserved
tmp2(b(c),:)
ans =
1.1000 19.1000
1.2000 19.1000
1.0000 20.4000
0.7000 20.4000
1.0000 20.4000
1.4000 19.1000
0.6000 20.4000
0.9000 20.4000
1.3000 19.1000
0.8000 20.4000
...
which still preserves the last entry found. If you want to keep the first entry found, use
% unique values, order preserved, keep first occurrence
[a,b,c] = unique(tmp2(:,1), 'first');
I saw the solution with unique, and wanted to give a solution with loops. You can take a look to see which one is faster :D! The loop could probably be ameliorated...
clear
tmp = [0.6000 20.4000
0.7000 20.4000
0.8000 20.4000
0.9000 20.4000
1.0000 20.4000
1.0000 19.1000
1.1000 19.1000
1.2000 19.1000
1.3000 19.1000
1.4000 19.1000];
ltmp = length(tmp);
jj = 1;
for ii = 1 : ltmp
if ii > 1
if tmp(ii, 1) == tmp(ii - 1, 1)
continue
end
end
if ii < ltmp
if tmp(ii, 1) == tmp(ii + 1, 1)
tmp2(jj,1) = tmp(ii, 1);
tmp2(jj,2) = min(tmp(ii, 2),tmp(ii + 1, 2));
else
tmp2(jj, 1) = tmp(ii, 1);
tmp2(jj, 2) = tmp(ii, 2);
end
else
tmp2(jj, 1) = tmp(ii, 1);
tmp2(jj, 2) = tmp(ii, 2);
end
jj = jj + 1;
end