Invalid regular expression error

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清酒与你
清酒与你 2021-01-19 06:35


I\'m trying to retrieve the category part this string \"property_id=516&category=featured-properties\", so the result should be \"featured-properties\

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  • 2021-01-19 06:58

    If you want to parse URL parameters, you can use the getParameterByName() function from this site:

    • http://james.padolsey.com/javascript/bujs-1-getparameterbyname/

    In any case, as already mentioned, regular expressions in JavaScript are not plain strings:

    • https://developer.mozilla.org/en/JavaScript/Guide/Regular_Expressions
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  • 2021-01-19 07:02

    Positive lookbehinds (your ?<=) are not supported in JavaScript environments that do not comply with ECMAScript 2018 standard, which is causing your RegEx to fail.

    You can mimic them in a whole bunch of different ways, but this might be a simpler RegEx to get the job done for you:

    var url = "property_id=516&category=featured-properties"
    var urlRE = url.match(/category=([^&]+)/);
    // urlRE => ["category=featured-properties","featured-properties"]
    // urlRE[1] => "featured-properties"
    

    That's a super-simple example, but searching StackOverflow for a RegEx pattern to parse URL parameters will turn up more robust examples if you need them.

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  • 2021-01-19 07:04

    The syntax is messing up your code.

    var urlRE = url.match(/category=([a-z-]+)/);
    alert(urlRE[1]);
    
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  • 2021-01-19 07:04
      var url = "property_id=516&category=featured-properties",
    
      urlRE = url.match(/(category=)([a-z-]+)/i); //don't forget i if you want to match also uppercase letters in category "property_id=516&category=Featured-Properties"
      //urlRE = url.match(/(?<=(category=))[a-z-]+/i); //this is a mess
    
      alert(urlRE[2]); 
    
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