How to zero array members when my compiler isn't standard conform

Question

My compiler (C++Builder6) syntactically allows array member initialization (at least with zero), but actually it doesn\'t really do it. So the assert in the example given be

Answer 1

I think you may use this:

TT() { std::fill(b, b + 8, char()); }

This way you will solve your problem while nothing is wrong with portability and standard conformance!

Answer 2

You may use fill_n like suggested in: C/C++ initialization of a normal array with one default value

If no fill_n is available, you can always use memset like:

TT() {memset(b, 0, sizeof b);}

Answer 3

I would like to append previous posts that if you are using a character array as a string then it is enough to write in the constructor

TT() { b[0] = '\0'; }