I have the following code which will start after clicking the \'Start\' button in PyQt:
def Start(self):
import time
import os
import RPi.GPIO as GPIO
This question is useful: tkinter loop and serial write It could be copied over with two changes: master.update
becomes QtGui.qApp.processEvents
and master.after
becomes QTimer.singleShot
.
Here is a sketch of how to do what you ask for with guiLoop:
from guiLoop import guiLoop, stopLoop
# ... means fill in your code
class ...:
started = False
def Start(self):
if not self.started:
# you can also use threads here, see the first link
self.started = self.StartLoop()
def Stop(self):
if self.started:
stopLoop(self.started)
self.started = False
@guiLoop
def StartLoop(self):
# This is your Start function
# ...
while True:
# ...
yield 0.085 # time.sleep(0.085) equivalent
# ...
Since I do not know what your code look like, here is a working example using PyQT4 and guiLoop:
from PyQt4 import QtGui
import sys
from guiLoop import guiLoop # https://gist.github.com/niccokunzmann/8673951
@guiLoop
def led_blink(argument):
while 1:
print("LED on " + argument)
yield 0.5 # time to wait
print("LED off " + argument)
yield 0.5
app = QtGui.QApplication(sys.argv)
w = QtGui.QWidget()
w.resize(250, 150)
w.move(300, 300)
w.setWindowTitle('Simple')
w.show()
led_blink(w, 'shiny!')
sys.exit(app.exec_())
guiLoop
uses QTimer.singleShot(time, function)
to make the loop continue.
You can also stop the loop with stopLoop()
of guiLoop.
There is no need to do anything other than what I suggested in your other question on this topic: just use processEvents
. As long as you can call it frequently enough (but not too frequently), it should do exactly what you want. Using your second example, the following works fine for me:
def Start(self):
if not self.started:
self.started = True
self.StartLoop()
def Stop(self):
if self.started:
self.started = False
def StartLoop(self):
DEBUG = 1
while self.started:
print "LED on "
time.sleep(0.05)
print "LED off "
time.sleep(0.085)
QtGui.qApp.processEvents()