How does FOLLOW work for the following CFG?

前端 未结 0 1739
盖世英雄少女心
盖世英雄少女心 2021-01-19 04:38

The original cfg is

S -> S + S | SS | (S) | S* | a

After refactoring and eliminating left recursion, I arrive at the following reduction:<

相关标签:
回答
  • 消灭零回复
提交回复
热议问题