How to print list item + integer/string using logging in Python

Question

I\'d like to print list item with the index of item such as

0: [(\'idx\', 10), (\'degree\', 0)]
1: [(\'idx\', 20), (\'degree\', 0)]

Based o

Answer 1

I would do it like this.

def funcA():
    a = []
    a.append(Node(10, 0))
    a.append(Node(20, 0))

    for i in range(0, len(a)):
        message = '%s:%s' % (i, a[i].items())
        logging.debug(message)

Which produces this as output:

DEBUG:root:0:[('idx', 10), ('degree', 0)]
DEBUG:root:1:[('idx', 20), ('degree', 0)]

You could also use join:

message = ':'.join([str(i), str(a[i].items())])

Or format:

message = '{0}:{1}'.format(str(i), a[i].items())

Whatever is the most clear to you.

Answer 2

with Python > 3.6 you can use fstring

logging.debug(f"{i}:{a[i].items()}")