Calculating the sum of integers in an array

Question

I don\'t know if I\'m just being a total fool, most likely I am, it\'s been a long day, but this isn\'t working as I want it to, and, well, I don\'t see why.

It sho

Answer 1

You have 10 elements in the array, numbered 0 - 9. You are overflowing the buffer, so all bets are off. This is undefined behaviour.

Answer 2

You can't add eleven entries to a ten-element array.

Answer 3

If an array is a[10], then every array starts from its index number 0, so here it will have 10 elements; given that their positions will start from 0 to 9, counting gives 10 elements.

You can try this:

main()         
{        
    int a[10], i, n, sum=0;    

    printf("enter no. of elements");
    scanf("%d",&n); 
    printf("enter the elements");   

    for(i=0;i<n;i++)    
        scanf("%d",&a[i]);

    for (i=0;i<n;i++)
        sum=sum+a[i];

    for(i=0;i<n;i++)
        printf("\n a[%d] = %d", i, a[i]);

    printf("\n sum = %d",sum);
    getch();

}

Answer 4

You have problems with your array declaration. You are defining an array of size 10 array[10] and saying the program to calculate the sum of 11 elements which is resulting in memory overflows.

To correct the program just increase size of the array as array[11]. Also if you wish you can check the recursive approach to find sum of array elements.

Answer 5

int main()
{
    int a[10];
    int i,j;
    int x=0;
    printf("Enter no of arrays:");
    scanf("%d",&j);
    printf("Enter nos:");
    for(i=0;i<j;i++)
    {
        scanf("%d",&a[i]);
    }
    for (i=0;i<j;i++)
    {
        x=x+a[i];
    }
    printf("Sum of Array=%d",x);
    return 0;
}

Answer 6

int main()
{
    //this the sum of integers in an array
    int array[] = { 22,2,2,1,5,4,5,7,9,54,4,5,4 },x,sum=0;
    int cout_elements = sizeof(array) / sizeof(int);
    for (x = 0; x < cout_elements; x++) {
        
        sum += array[x];

    }
    printf("%d",sum);
    return 0;
}