MySQL order by two values

Question

In short, I have a game of sorts, and the score board for it shows the score of the player at the end + how long they took to achieve it. I need to order my MySQL results so

Answer 1

You should be use below code.. Its working.

$query = "SELECT field1, field2 from tablename ORDER BY field1 DESC, field2 DESC";

Answer 2

you should use an integer column for time instead of a varchar,
that's mean convert 00:19:32 to just 1172 seconds,
then is pretty easy for sort

Answer 3

I think this is the best solution for arrange order by multiple value.

 SELECT * FROM hotel   
   WHERE confId=13   
   GROUP BY hotelName   
   ORDER BY CASE
   WHEN rating = '5 Star' THEN 1 WHEN rating = '4 Star' THEN 2   
   WHEN rating = '3 Star' THEN 3 WHEN rating = 'BUDGET & EQUIVALENT HOTELS' THEN 4 
 END

Answer 4

just try

$sql1 = "SELECT * FROM boobmatch_highscores ORDER BY t_score * time DESC";

Answer 5

You query is supposed to work perfectly. If you have any issues just enclose the field names in quotes like so:

$sql1 = "SELECT * FROM boobmatch_highscores ORDER BY `t_score` DESC, `time` ASC";

Guessing it's MySQL, else the quotes won't be necessary

Answer 6

You've to use this query:

select * from boobmatch_highscores order by time ASC, t_score DESC

Now time is displayed ascending order and score is displayed descending order.