I\'ve been led to understand that calling a member function on the contents of a moved-from std::unique_ptr
is undefined behaviour. My question is: if I call
Merely moving the unique_ptr
only changes the ownership on the pointed-to object, but does not invalidate (delete) it. The pointer pointed to by unique_ptr<>::get()
will be valid as long as it hasn't been deleted. It will be deleted, for example, by the destructor of an owning unique_ptr<>
. Thus:
obj*ptr = nullptr; // an observing pointer
{
std::unique_ptr<obj> p1;
{
std::unique_ptr<obj> p2(new obj); // p2 is owner
ptr = p2.get(); // ptr is copy of contents of p2
/* ... */ // ptr is valid
p1 = std::move(p2); // p1 becomes new owner
/* ... */ // ptr is valid but p2-> is not
} // p2 destroyed: no effect on ptr
/* ... */ // ptr still valid
} // p1 destroyed: object deleted
/* ... */ // ptr invalid!
Of course, you must never try to use a unique_ptr
that has been moved from, because a moved-from unique_ptr
has no contents. Thus
std::unique_ptr<obj> p1(new obj);
std::unique_ptr<obj> p2 = std::move(p1);
p1->call_member(); // undefined behaviour