setw() does not affect reading integer fields

Question

I wrote a code like this:

int d{ 0 };
cin >> setw(2) >> d;

But it seems setw() has no effect on reading integers.

Answer 1

setw() is not designed to be used with integral types.

What would it do? Extract the last two decimal digits of the integer? What would happen if you had put std::hex into the stream?

The best approach is to read the number then deal with it yourself. For example, if you want to extract the least significant two digits, use d % 100 subsequently; making an extra correction for negative numbers.