Django upload image - From a form to Rackspace/S3 with no manipulation

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I simply want to upload an image (JPG) using a form, then send that image to Rackspace \'Cloud Files\' or Amazon \'S3\'.

No manipulating the file.
No

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2条回答

半阙折子戏

2021-01-19 01:46

How about ignoring python all together and just uploading directly to s3?

You can configure your s3 bucket to disallow uploading any files larger than $X bytes.

Here's a simple example to illustrate uploading directly to s3 (and ignoring your image width/height conditions)

http://sente.cc/upload_to_s3.html

code:

<html>
  <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
  </head>
  <body>
  <h3>refresh the page after you've submitted to see your new image</h3>
    <div style="width:300px">
    <form action="http://s3.amazonaws.com/dev.sente" method="post" enctype="multipart/form-data">
      <fieldset>
      <input type="hidden" name="acl" value="public-read" /> <br />
      <i>name of key:</i><input type="text" name="key" readonly="true" value="image.jpg" /> <br />
      <input name="file" type="file" /> <br />
      <input name="submit" value="Upload" type="submit" />
    </fieldset>
    </form>
  </div>
    <br>
    <a href="http://s3.amazonaws.com/dev.sente/image.jpg">http://s3.amazonaws.com/dev.sente/image.jpg</a>
      <br>
      <a href="http://s3.amazonaws.com/dev.sente/image.jpg"><img src="http://s3.amazonaws.com/dev.sente/image.jpg"></a>
    </a>
  </body>
</html>

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情话喂你

2021-01-19 01:47
Sorted out. Found a simpler elegant approach and feel stupid for not getting to it earlier.
```
file = request.FILES["item_photo"]
file_name = "%s/%s" % (id, '600.jpeg')
put_file(container, file_name, file.read())
```
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