Generate random between 0 - 9 but not 6 [closed]

Answer 1

I'm going to be lazy here and take @H2CO3's answer to be working without trying it.

<script type="text/javascript">

function generate(var UNWANTED) {
    var r;
    do {
        r = Math.floor(Math.random() * 10);
    } while (r == UNWANTED);
    return r;
}

function GENERATE_RANDOM_FROM_0_TO_10_BUT_NOT_6_OR_SOMETHING_ELSE_(var NOT_GOOD){
    return generate(NOT_GOOD)     <== One line solution.
}
<script>

Answer 2

The naïve approach:

var r;
do {
    r = Math.floor(Math.random() * 10);
} while (r == 6);

Answer 3

Try this:

var rr=(Math.floor(Math.random()*10));
result=(rr==6)?1:rr;

Edit:
The probability of 1 is not likely other, so I made it to recursive if it generate 6.

function notSix() {
  var rr=(Math.floor(Math.random()*10));
  return (rr==6)?notSix():rr;
}

notSix()

Correcting the first example:
generating between 0-8 first and if outputs 6 converting to 9;

var rr=(Math.floor(Math.random()*9));
result=(rr==6)?9:rr;

Answer 4

Generate a random number between 0 and 8 and then add 1 if it's >=6

Answer 5

Here is your one line solution :(

[0,1,2,3,4,5,7,8,9][Math.floor(Math.random()*9)]

Answer 6

var n = (n = Math.floor(Math.random() * 9)) == 6 ? 9 : n;