XSL msxsl:node-set problem

Question

Please help me out guys. I\'m just trying to declare a simple result tree fragment and iterate over it.

---

...

Answer 1

My suspicion is that you have a default namespace declared in your stylesheet. That would effectively place the <item-list> and <item> elements into a namespace. To select namespace-qualified elements using XPath 1.0, you must always use a prefix in the expression.

So if you have something like this at the top of your stylesheet:

<xsl:stylesheet xmlns="http://example.com"...>

Then you'll need to also add this:

<xsl:stylesheet xmlns="http://example.com" xmlns:x="http://example.com"...>

And then use the "x" prefix in your XPath expression:

<xsl:for-each select="msxsl:node-set($rtf)/x:item-list/x:item">
  <xsl:value-of select="@id"/>
</xsl:for-each>

Let me know if that did the trick. I'm only speculating here.

Answer 2

Unlike MSXSL, XslCompiledTransform provides node-set() function where it is supposed to be - in EXSLT Common namespace:

<xsl:stylesheet xmlns:exslt="http://exslt.org/common">
  ...
  <xsl:for-each select="exslt:node-set($rtf)/item-list/item">
  ...
</xsl:stylesheet>

Answer 3

This looks OK to me.

Have you correctly declared the msxsl namespace for the extension functions though? Something like this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt">

I am assuming you are using the Microsoft XSLT processor here