How to write a template function that takes an array and an int specifying array size

Question

For a university exercise, I have been asked to write a template function \"print();\", which takes two arguments, 1: an array of a generic type, and 2: an int specifying t

Answer 1

The correct way to write it is

Live On Coliru

#include <iostream>

template <typename T, size_t size> void print(const T (&array)[size])
{
    for(size_t i = 0; i < size; ++i)
        std::cout << array[i] << " ";
}

int main() {
    int arr[] = { 1,2,3,4,99};

    print(arr);
}

Prints

1 2 3 4 99

Answer 2

If you want to pass the array by reference, you could

template <typename T, size_t SIZE>
void print(const T(&array)[SIZE])
{
    for (size_t i = 0; i < SIZE; i++)
        std::cout << array[i] << " ";
}

and then, e.g.

int x[] = {1, 2, 3};
print(x);

LIVE

Otherwise, you can pass it by pointer, note that the array will decay to pointer, and you have to guarantee the correctness of SIZE being passed.

template <typename T>
void print(const T array[], size_t SIZE)
{
    for(size_t i = 0; i < SIZE; i++)
        std::cout << array[i] << " ";
}

and then, e.g.

int x[] = {1, 2, 3};
print(x, sizeof(x) / sizeof(int));

LIVE