private func createWeatherObjectWith(json: Data, x:Any.Type ,completion: @escaping (_ data: Any?, _ error: Error?) -> Void) {
do {
let decode
If you are trying to decode any type of object then use these technique
1. Generics function
private func createWeatherObjectWith<T: Decodable>(json: Data, Object:T.Type ,completion: @escaping (_ data: T?, _ error: Error?) -> Void) {
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
let weather = try decoder.decode(T.self, from: json)
return completion(weather, nil)
} catch let error {
return completion(nil, error)
}
}
2. Extend Decodable
extension Decodable {
static func map(JSONString:String) -> Self? {
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
return try decoder.decode(Self.self, from: Data(JSONString.utf8))
} catch let error {
print(error)
return nil
}
}
}
Use:
let user = User.map(JSONString:"your JSON string")
let users = [User].map(JSONString:"your JSON string")
Trying to decode any type of Object to String in Swift 4.1
func convertAnyObjectToJSONString(from object:Any) -> String? {
guard let data = try? JSONSerialization.data(withJSONObject: object, options: []) else {
return nil
}
return String(data: data, encoding: String.Encoding.utf8)
}